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If radius of the `._13^27 A1` nucleus is taken to be `R_(A1)` then the radius of `._53^125 Te` nucleus is nearly.A. `((53)/(13))^(1//3) R_(A1)`B. `(5)/(3) R_(A1)`C. `(3)/(5) R_(A1)`D. `((13)/(53))^(1//3) R_(A1)` |
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Answer» Correct Answer - B (b) As we know, `R = R_0 (A)^(1//3)` Where `A` = mass number `R_(A1) = R_0 (27)^(1//3) = 3 R_0` `R_(Te) = R_0 (125)^(1//3) = 5 R_0 = (5)/(3) R_(A1)`. |
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