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If sec `alpha and alpha`are the roots of `x^2-p x+q=0,`then(a) `p^2=q(q-2)`(b) `p^2=q(q+2)`(c)`p^2q^2=2q`(d) none of these |
Answer» a)`p^2=alpha^2+secc^2alpha+2alphasecalpha` `q(q-2)=alphasecalpha(alphasecalpha-2)` `=alpha^2sec^2alpha-2alphasecalpha` `p^2!=q(q-2)` b)`q(q+2)=alpha^2sec^2alpha+2alphasecalpha!=(alpha+secalpha)^2` c)`p^2q^2=(alpha^2+sec^2alpha+2alphasecalpha)(alpha^2sec^2alpha)` `=alpha^4secc^4alpha+alpha^2secc^4alpha+2alpha^3sec^3alpha` `2q=2alphasecalpha` `p^2q^2!=2q` d)none. |
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