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if `sin^2theta=(x^2+y^2+1)/(2x)` then `x` must beA. -3B. -2C. 1D. None of these |
Answer» Correct Answer - C `sin^2thetale1` `rArr (x^2+y^2+1)/(2x)le1` `orx^2+y^2-2x+1le0 (asxgt0)` `or (x-1)^2+y^2le0` It is possible if x - 1 = 0 and y = 0. |
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