If sin 3θ = cos(θ – 6°) here 3θ and (θ – 6°) are acute angle

1.	If sin 3θ = cos(θ – 6°) here 3θ and (θ – 6°) are acute angles, then find the value of θ.
Answer» Given : sin 3θ = cos(θ – 6°) or cos(90° – 3θ) = cos(θ – 6°) [∵ cos(90° – θ) = sin θ] or 90° – 3θ = θ – 6° or 3θ + θ = 90° + 6° or 4θ = 96° or θ = 96/4 = 24°

If sin 3θ = cos(θ – 6°) here 3θ and (θ – 6°) are acute angles, then find the value of θ.

Answer»

Given :

sin 3θ = cos(θ – 6°)

or cos(90° – 3θ) = cos(θ – 6°) [∵ cos(90° – θ) = sin θ]

or 90° – 3θ = θ – 6°

or 3θ + θ = 90° + 6°

or 4θ = 96°

or θ = 96/4 = 24°