Related InterviewSolutions

• Prove the following trigonometric identities:cotθ - tanθ =\(\frac{2cos^2θ-1}{sinθ.cosθ}\)
• If sin 3θ = cos(θ – 6°) here 3θ and (θ – 6°) are acute angles, then find the value of θ.
• Verify the followingwith the help of identities.(i) ((1 + cotθ + tanθ)(sinθ - cosθ))/(sec3θ - cosec3θ) = sin2θ cos2θ(ii) (sinθ + cosθ)/(sinθ - cosθ) + (sinθ - cosθ)/(sinθ + cosθ) = 2/(1 - 2cos2θ) = 2/(2cos2θ - 1)
• In the adjoining figure, ∠B = 90°, ∠BAC = θ°, BC = CD = 4 cm and AD=10 cm. Find (i) sinθ and (ii) cosθ.