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If `sin51^(@)=(a)/sqrt(a^(2)+b^(2))` then find the value of `tan39^(@)` |
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Answer» `sin51^(@)=(a)/sqrt(a^(2)+b^(2))orsin^(2)51^(@)=(a^(2))/(a^(2)+b^(2))` or, `sin^(2)(90^(@)-39^(@))=(a^(2))/(a^(2)+b^(2))or,cos^(2)39^(@)=(a^(2))/(a^(2)+b^(2))` or, `sec^(2)39^(@)(a^(2)+b^(2))/(a^(a))or,1+tan^(2)39^(@)=(a^(2)+b^(2))/(a^(2))` `tan^(2)39^(@)=(a^(2)+b^(2))/(a^(2))-1` `tan^(2)39^(@)=(a^(2)+b^(2)-a^(2))/(a^(2))ortan^(2)39^(@)=(b^(2))/(a^(2))` or, `tan39^(@)=(b)/(a)` Hence `tan39^(@)=(b)/(a)`. |
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