If `sinA=sin^2B and 2cos^2A=3cos^2B` then the triangle ABC isA. right – InterviewSolution

InterviewSolution

1.	If `sinA=sin^2B and 2cos^2A=3cos^2B` then the triangle ABC isA. right angledB. obtuse angledC. ospscelesD. equilateral
Answer» Correct Answer - B `sinA=sin^2Band2cos^2A=3cos^2B` `rArr2-2sin^2A=3-3sin^2B` `rArr2sin^2A-3sinA+1=0` `rArr(2sinA-1)(sinA-1)=0` `rArrA=30^@rArrA=90^@` If `A=30^@rArrB=45^@rArrC=105^@` If `A=90^@rArrB=90^@`, which is not possible

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