InterviewSolution
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InterviewSolution
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If `sintheta=a/b`, then `costheta` is equal toA. `b/(sqrt(b^(2)-a^(a))`B. `b/a`C. `(sqrtb^(2)-a^(2))/b`D. `a/(sqrt(b^(2)-a^(2))` |
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Answer» Correct Answer - C Given, `sintheta=a/b` `[therefore sin^(2)theta+ cos^(2)theta=1 rArr costheta=sqrt(1-sin^(2)theta)]` `therefore costheta=sqrt(1-sin^(2)theta)` `=sqrt(1-(a/b)^(2)) = sqrt(1-a^(2)/b^(2))= (sqrtb^(2)-a^(2))/b` |
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