If `sinx+cosecx=2," then "sin^nx+cosec^nx` is equal toA. 2B. `2^n`C. ` – InterviewSolution

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1.	If `sinx+cosecx=2," then "sin^nx+cosec^nx` is equal toA. 2B. `2^n`C. `2^(n-1)`D. `2^(n-2)`
Answer» Correct Answer - A `sinx+cosecx=2` `or (sinx-1)^2=0` `or sinx=1` `rArr sin^nx+cosec^nx=1+1=2`

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