InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
If `tantheta+sintheta=mandtantheta-sintheta=n`,thenA. `m^2-n^2=4mn`B. `m^2+n^2=4mn`C. `m^2-n^2=m^2+n^2`D. `m^2-n^2=4sqrt(mn)` |
|
Answer» Correct Answer - D From the given relations, `m+n=2tantheta,m-n=2sintheta`. Thus,`m^2-n^2=4tanthetasintheta` Also `sqrt(mn)=sqrt(tan^2theta-sin^2theta)=sinthetatantheta` From Eqs. (i) and (ii), we get `m^2-n^2=4sqrt(mn)`. |
|