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If `tantheta+tan2theta+sqrt(3)tanthetatan2theta=sqrt(3)`, then `theta=(npi)/(3)+(pi)/(9)`.A. `(3n+1)(pi)/(9), ninZ`B. `(3n+1)(pi)/(6), ninZ`C. `(3n+1)(pi)/(3), ninZ`D. `(3n+1)(pi)/(18), ninZ` |
Answer» Correct Answer - A | |