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If ten volumes of dihydrogen gas reacts with five volumes of dioxygen gas, how many volumes of water vapour could be produced? |
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Answer» Solution :`H_(2) and O_(2)` react ACCORDING to the equation `H_(2(g))+O_(2(g))RARR 2H_(2)O_((g))` THUS, 2 volumes of `H_(2)` react with 1 volume of `O_(2)` to produce 2 volumes of water vapour. Hence, 10 volumes of `H_(2)` will react completely with 5 volumes of `O_(2)` to produce 10 volumes of water vapour. |
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