1.

If the angle of elevation of an object from a point 100 m above a lake is found to be 30° and the angle of depression of its image in lake is 45°, then the height of the object above the lake is

Answer»

`100(2-SQRT(3))m`
`100(2+sqrt(3))`m
`100(sqrt(3)-1)` METRES
`1000(sqrt(3)+1)` m

Answer :B


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