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If the diameter of a carbon atom is `0.15 nm`, calculate the number of carbon atom which can be placed side by side in a straight line length of scale of length `20 cm` long.A. `13.3 xx 10^(9)`B. `1.33 xx 10^(9)`C. `6.2 xx 10^(9)`D. `1.33 xx 10^(7)` |
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Answer» Correct Answer - B No of carbon items that can be placed in a straight line `= ("length")/("diameter")` |
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