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If the disintegration constant is `6.93 xx 10^(-6) yr^(-1)`, then half-life of `._(6)C^(14)` will beA. `10^(2) yr`B. `10^(3) yr`C. `10^(4) yr`D. `10^(5)yr` |
Answer» Correct Answer - D `t_(1//2) = (0.693)/(k) = (0.693)/(6.93 xx 10^(-6)) = 0.1 xx 10^(6) = 10^(5) yr` |
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