1.

If the energy different between the electronic stazte in `214.68 mol^(-1)` calculate the frequency of light emited when an electron drop form the hight to the lower state planks constant , `h = 39,79 xx 10^(-14)kJmol^(-1)`

Answer» Correct Answer - A::C::D
`Delta E = E_(2) - E_(1) = hv`
`:. 214.68 = 39.79 xx 10^(-14) xx v`
` or v = 5.39 xx 10^(14) xx cps`


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