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If the energy different between the electronic stazte in `214.68 mol^(-1)` calculate the frequency of light emited when an electron drop form the hight to the lower state planks constant , `h = 39,79 xx 10^(-14)kJmol^(-1)` |
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Answer» Correct Answer - A::C::D `Delta E = E_(2) - E_(1) = hv` `:. 214.68 = 39.79 xx 10^(-14) xx v` ` or v = 5.39 xx 10^(14) xx cps` |
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