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If the function `f(x)`defined byf(x)=`(log(1+3x)-"log"(1-2x))/x `, `x!=0` and k , x=0.Find k. |
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Answer» `f(x) = (log(1+3x) - log(1-2x))/x` `l = lim_(x->0) (log(1+3x) - log(1-2x))/x` `l = lim_(x->0) (1/(1+3x) * 3 - 1/(1-2x) (-2))/1` `l = lim_(x->0) 3/(1+3x) + 2/(1-2x) ` `l = 3/1 + 2/1 = 5` `f(0) = f(0^-) = f(0^+)` `k = 5` Answer |
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