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If the kinetic energy of a particle is doubled, de Broglie wavelength becomes:A. 2 timesB. 4 timesC. `sqrt(2)`timesD. `(1)/(sqrt(2))` times

Answer» Correct Answer - D
`lamda=(h)/(sqrt(2Em))` where E=Kinetic energy of the particle
`thereforelamda_(1)=(h)/(sqrt(2Em)),lamda_(2)=(h)/(sqrt(2xx2Em))`
`(lamda_(1))/(lamda_(2))=sqrt(2)` i.e., `lamda_(2)=(lamda_(1))/(sqrt(2))`


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