If the line, `(x-3)/2=(y+2)/(-1)=(z+4)/3`lies in the place, `l x+m y-z=9`, then `l^2+m^2`is equal to:(1) 26(2) 18(3) 5(4) 2A. 26B. 18C. 5D. 2

If the line, `(x-3)/2=(y+2)/(-1)=(z+4)/3`lies in the place, `l x+m y-z

1.	If the line, `(x-3)/2=(y+2)/(-1)=(z+4)/3`lies in the place, `l x+m y-z=9`, then `l^2+m^2`is equal to:(1) 26(2) 18(3) 5(4) 2A. 26B. 18C. 5D. 2
Answer» Correct Answer - D Since, the line `(x-3)/(2)=(y+2)/(-1)=(z+4)/(3)` line in the plane `lx+my-z=9,` therefore we have `2l-m-3=0` [`because` normal will be perpendicular to the line] `implies" "2l-m=3" "...(i)` and `" "3l-2m+4=9` [`because` point (3, -2, -4) lies on the plane] `implies" "3l-2m=5" "...(ii)` On solving Eqs. (i) and (ii), we get `l=1" and "m=-1` `:." "l^(2)+m^(2)=2`

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If the line, `(x-3)/2=(y+2)/(-1)=(z+4)/3`lies in the place, `l x+m y-z=9`, then `l^2+m^2`is equal to:(1) 26(2) 18(3) 5(4) 2A. 26B. 18C. 5D. 2

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