1.

If the linear momentum is increased by 50%, then kinetic energy will increase by

Answer»

0.5
1
1.25
0.25

Solution :`P^(1)=1.5P`, INITIAL K.E. `=(P^(2))/(2M)`, FIND K.E. `K^(-1)=(P^(12))/(2m)`
`K^(1)=2.25`
% increase `=(DELTAK)/Kxx100=125%`


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