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If the lines `a_1x+b_1y+1=0, a_2x+b_2y+1=0 a n d a_3x+b_3y+1=0`are concurrent, show that the points `(a_1, b_1), (a_2, b_2)a n d (a_3, b_3)`are collinear. |
Answer» The given lines are `a_ (1)x+b_(1)y+1=0` `a_(2)x+b_(2)y +1=0` ` a_(3) x+b_(3)y+1=0` if these lines are concurrent we must have3 `|underset(a_(3)" "b_(3)" "1)underset(a_(2)" "b_(2)" "1)(a_(1)" "b_(1)" "1)|=0` Which is the condition of colinearity of three points `(a_(1) b_(1)), (a_(2),b_(2)), " and " (a_(3),b_(3))` Hence if the given lies are concurrent the given points are collinear. |
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