1.

If the magnitude of two vectors are 3 and 4 and their scalar product is 6, find angle between them and also find |vecA xx vecB|.

Answer»

SOLUTION :`vecA. vecB=AB cos THETA,|vecA XX vecB|=AB SIN theta`
or `6 = (3xx4)cos theta"" = 3xx4 xx sin 60^(@)`
`or theta =60^(@)"" =3xx4xx(SQRT(3))/(2)=6sqrt(3)`


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