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If the magnitude of two vectors are 3 and 4 and their scalar product is 6, find angle between them and also find |vecA xx vecB|. |
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Answer» SOLUTION :`vecA. vecB=AB cos THETA,|vecA XX vecB|=AB SIN theta` or `6 = (3xx4)cos theta"" = 3xx4 xx sin 60^(@)` `or theta =60^(@)"" =3xx4xx(SQRT(3))/(2)=6sqrt(3)` |
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