1.

If the mass of proton= 1.008 a.m.u. and mass of neutron=1.009a.m.u. then binding energy per nucleon for `._(4)Be^9` (mass=9.012 amu) would be-A. 0.065 MeVB. 60 .44MeVC. 67.2 MeVD. 6.72 MeV

Answer» Correct Answer - B
Rest mass energy+kinetic energy =energy of gama photon
`0.51xx2MeV+2xxE_(k)=2.42 MeV`.
`E_(k)=0.7 MeV`


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