1.

If the median AD of triangle ABC makes an angle `pi/4`with the side BC, then find the value of `|cotB-cotC|dot`

Answer» By m-n theoram
`(m+n)cottheta=mcotalpha-cotbeta`
`(m+n)cottheta=ncotbeta-mcotC`
`(BD+DC)cot(x/4)=DC cot B-BD cotC`
`BD+DC=DC cot B-BD cotC`
`2BD=BD cot B- BD cot C`
`|cotB-cotC|=2`.


Discussion

No Comment Found