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If the nuclear radius of `.^27 A1` is `3.6` Fermi, the approximate nuclear radius of `64 Cu` in Fermi is :A. 3.6B. 2.4C. 1.2D. 4.8 |
Answer» Correct Answer - D (d) Nuclear radius `r prop A^(1//3)`, where `A` is mass number `r = r_0(27)^(1//3) = 3 r_0 rArr r_0 = (3.6)/(3) = 1.2 fm` For `.^64 Cu, r = r_0 A^(1//3) = 1.2 fm (64)^(1//3) = 4.8 fm`. |
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