InterviewSolution
Saved Bookmarks
| 1. |
If the osmotic pressure of glucose solution is 1.52 bar at 300 K. What would be its concentration if R = 0.083L bar `"mol"^(-1)"K"^(-1)` ? |
|
Answer» `pi = "CRT"` `R=0.0836."bar. mole"^(-1)"K"^(-1)` T = 300 K `pi = 1.52" bar"` `C = (pi)/("RT")=(1.52)/(0.083xx300)=(1.52)/(24.9)=0.061" M"` |
|