1.

If the radius of the Earth shrinks by 2%, mass remaing same, then how would the have of acceleration due to gravity change?

Answer»

Solution :`g=(Gm^2)/(R^2)`
TAKING logarithm `LOG g = log G+2log m-2log R`
Differenntiating it `(dg)/(g)=0+0-2(dR)/(R )= -2[(-2)/(100)]`
`(dg)/(g)xx100= -2[(-2)/(100)]xx100=4%`.


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