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If the refractive index of second medium with respect to first medium is "_(2)n_(1) and that of third medium with respect to second to medium is "_(3)n_(2), what and how much is "_(3)n_(1) ? |
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Answer» SOLUTION :`_(2)n_(1)=("Velocity of LIGHT in MEDIUM" 1 (V_(1)))/("Velocity of light in medium"2 (V_(2)))""....(i)` `_(3)n_(2)=("Velocity of light in medium" 2 (V_(2)))/("Velocity of light in medium"3 (V_(3)))""....(ii)` `_(3)n_(1)=("Velocity of light in medium" 2 (V_(1)))/("Velocity of light in medium"3 (V_(3)))""....(iii)` Multiply (i) and (ii) `""_(2)n_(1)xx""_(3)n_(2)=("Velocity of light in medium" 1 (V_(1)))/("Velocity of light in medium"2 (V_(2)))xx("Velocity of light in medium" 2 (V_(2)))/("Velocity of light in medium"3 (V_(3)))"` `""_(2)n_(1)xx""_(3)n_(2)=("Velocity of light in medium" 1 (V_(1)))/("Velocity of light in medium"2 (V_(3)))` `:.""_(2)n_(1)xx""_(3)n_(2)=""_(3)n_(1) ""..."from" (iii)` |
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