1.

If the refractive index of second medium with respect to first medium is "_(2)n_(1) and that of third medium with respect to second to medium is "_(3)n_(2), what and how much is "_(3)n_(1) ?

Answer»

SOLUTION :`_(2)n_(1)=("Velocity of LIGHT in MEDIUM" 1 (V_(1)))/("Velocity of light in medium"2 (V_(2)))""....(i)`
`_(3)n_(2)=("Velocity of light in medium" 2 (V_(2)))/("Velocity of light in medium"3 (V_(3)))""....(ii)`
`_(3)n_(1)=("Velocity of light in medium" 2 (V_(1)))/("Velocity of light in medium"3 (V_(3)))""....(iii)`
Multiply (i) and (ii)
`""_(2)n_(1)xx""_(3)n_(2)=("Velocity of light in medium" 1 (V_(1)))/("Velocity of light in medium"2 (V_(2)))xx("Velocity of light in medium" 2 (V_(2)))/("Velocity of light in medium"3 (V_(3)))"`
`""_(2)n_(1)xx""_(3)n_(2)=("Velocity of light in medium" 1 (V_(1)))/("Velocity of light in medium"2 (V_(3)))`
`:.""_(2)n_(1)xx""_(3)n_(2)=""_(3)n_(1) ""..."from" (iii)`


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