If the resistances 3Ω, 5Ω, 7Ω, 9Ω are in series, then their equivalent resistance(Ω) is?(a) 9(b) 20(c) 24(d) 32I have been asked this question in final exam.This intriguing question originated from Circuit Elements and Kirchhoff’s Laws in division Circuit Elements and Kirchhoff’s Laws of Network Theory

If the resistances 3Ω, 5Ω, 7Ω, 9Ω are in series, then their eq

1.	If the resistances 3Ω, 5Ω, 7Ω, 9Ω are in series, then their equivalent resistance(Ω) is?(a) 9(b) 20(c) 24(d) 32I have been asked this question in final exam.This intriguing question originated from Circuit Elements and Kirchhoff’s Laws in division Circuit Elements and Kirchhoff’s Laws of Network Theory
Answer» Correct ANSWER is (c) 24 Easy explanation: If the RESISTANCES are in SERIES, then equivalent RESISTANCE is the SUM of all the resistances that are in series. Equivalent resistance is (3+5+7+9)Ω = 24Ω.

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