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If the straight line x/a+y/b = 1 passes through the points (8, -9) and (12, -15), find the values of a and b. |
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Answer» To Find: The values of a and b when the line x/a+y/b = 1 passes through the points (8, -9) and (12, -15). Given: the equation of the line: x/a+y/b = 1 equation 1 Also (8, -9) passes through equation 1 8/a - 9/b = 1 8b - 9a = ab equation 2 And (12, -15) passes through equation 1 12/a − 15/b = 1 12b - 15a = ab equation 3 Solving equation 2 and 3 a = 2. Put a = 2 in equation 2 8b - 9a = ab 8b -18 = 2b 6b = 18 ⟹ b = 3 Hence the values of a and b are 2 and 3 respectively. |
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