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If the terminal speed of a sphere of gold (density `=19.5kg//m^3`) is `0.2m//s` in a viscous liquid (density `=1.5kg//m^3`), find the terminal speed of a sphere of silver (density `=10.5kg//m^3`) of the same size in the same liquidA. `0.4 m//s`B. `0.133 m//s`C. `0.1 m//s`D. `0.2 m//s` |
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Answer» Correct Answer - C Terminal speed of spherical body in a viscous liquid is given by `v_T = (2 r^2(rho - sigma)g)/(9 eta)` where `rho` = density of substance of body and `sigma` = density of liquid From given data `(v_T(Ag))/(v_T(Gold)) = (rho_(Ag) - sigma_l)/(rho_(Gold) - sigma_l)` `rArr v_t (Ag) = (10.5 - 1.5)/(19.5 - 1.5) xx 0.2 = (9)/(18) xx 0.2` =` 0.1 m//s`. |
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