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If the total vapour presure of the liquid mixture`A`and`B`is given by the equation:`P=180X_(A)+90`then the ratio of the vapour pressure of the pure liquids A and B is given by :A. `3:2`B. `4:1`C. `3:1`D. `6:2` |
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Answer» Correct Answer - C As we know `PT=P_(A)^(@)X_(S)+P_(B)^(@)X_(A)` `=P_(A)^(@)X_(A)+P_(B)^(@)(1-X_(A))=(P_(A)^(@)-P_(B)^(@))X_(A)+P_(B)^(@)…(1)` But from question,`P_(T)=180X_(A)+90...(2)` Equating equation(1)and(2) `:.P_(A)^(@)-P_(B)^(@)=180` `P_(B)^(@)=90,P_(A)^(@)=180+90=270` `(P_(A)^(@))/(P_(B)^(@))=(270)/(90)=3:1` |
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