If the uncertainnty in the position of a moving electron is equal to its de Broglie wavelength then moving its velocity will be completely anertain Explain .

If the uncertainnty in the position of a moving electron is equal to i

1.	If the uncertainnty in the position of a moving electron is equal to its de Broglie wavelength then moving its velocity will be completely anertain Explain .
Answer» Given that the uncertainty in position `(delta x)` is equal to de Broglie wavelength `(lambda)i.e. Delta x = lambda ` But according to de Broglie equation `lambda = (h)/(mv) = (h)/(p)` `or Delta x = (h)/(p)` (Given condition ) According to Heisenbegy uncertainty principle `(Delta x) (Delta p) ge (h)/(4pi)` `((h)/(p)) Delta p ge (h)/(4pi)` `(Delta cancel p)/(cancel p) ge (cancelh)/(4pi xx cancel h)` `(Delta cancel p)/(cancel p) ge (1)/(4pi)` (constant)

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If the uncertainnty in the position of a moving electron is equal to its de Broglie wavelength then moving its velocity will be completely anertain Explain .

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