1.

If the value of `E=-78.4 "kcal//mol"`, the order of the orbit in hydrogen atom is-A. `4`B. `3`C. `2`D. `1`

Answer» Correct Answer - C
`E=-78.4 kcal//mol`
`E_(n)=-313.6xx(Z^(2))/(n^(2))kcal//mol`
for `H` atoom `Z=1 " "-78.4=313.6xx(1)/(n^(2))`
`n^(2)=(313.6)/(78.4)" "n=2`


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