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If the value of the determinant \(\begin{vmatrix} 5 & \rm k\\ 3 & 3 \end{vmatrix}\)is 24, find the value of k.1. 22. 33. -34. -4 |
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Answer» Correct Answer - Option 3 : -3 Concept: If \({\rm{A}} = \left[ {\begin{array}{*{20}{c}} {{{\rm{a}}_{11}}}&{{{\rm{a}}_{12}}}\\ {{{\rm{a}}_{21}}}&{{{\rm{a}}_{22}}} \end{array}} \right]\) then determinant of A is given by: |A| = a11 × a22 – a21 × a12 Calculation: Let A = \(\begin{vmatrix} 5 & \rm k\\ 3 & 3 \end{vmatrix}\) Given that, the value of the determinant is 24. |A| = 24 ⇒ 15 - 3k = 24 ⇒15 - 24 = 3k ⇒ 3k = -9 ∴ k = -3 |
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