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If the vapour pressure of pure A and pure B at 298 K are 60 and 15 torr respectively, what would be the mole fraction of A in vapour phase (at this temperature) in a solution that contains 20 mole per cent of A in the (A + B) binary mixture in liquid phase ?A. 0.2B. 0.3C. 0.5D. 0.7 |
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Answer» Correct Answer - C `x_(A)=(20)/(100)=0.2,:.x_(B)=0.8` `p=p_(A)+p_(B)=p_(A)^(0)x_(A)+p_(B)^(0)x_(B)` `= 60xx0.2+15xx0.8=12+12=24` Mole fraction of A in the vapour phase, i.e., `y_(A)` may be calculatd as : `p_(A)=y_(A)xxp` `12=y_(A)xx24` `y_(A)=(12)/(24)=0.5`] |
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