1.

If the velocity of an electron in the first orbit of hydrogen atom is approximately `2.2xx10^(8) cm//s` is velocity in the fourth orbit would beA. `5.5xx10^(7)cm//s`B. `4.4xx10^(7)cm//s`C. `3.3xx10^(7)cm//s`D. `6.6xx10^(7)cm//s`

Answer» Correct Answer - A
`mvr=(nh)/(2pi)`
`v=(hn)/(2pimr)`
`v_(1)/v_(2)=r_(2)/r_(1)rArrv_(2)=(r_(1)/r_(2))V_(1)rArrv_(2)=1/4V_(1)`
`V_(2)=1/4xx2.2xx10^(8)`
`v_(2)=0.55xx10^(8)cm//s`
`=5.5xx10^(7)cm//s`


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