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If the velocity of hydrogen molecule is `5 xx 10^4 cm sec^-1`, then its de-Broglie wavelength is.A. `2 Å`B. `4 Å`C. `8 Å`D. `100 Å` |
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Answer» Correct Answer - B (b) According to de-Broglie `lamda = (h)/(mv) = (6.62 xx 10^-20 erg.sec)/((2)/(6.023 xx 10^23) xx 5 xx 10^4 cm//sec)` =`(6.62 xx 10^-27 xx 6.023 xx 10^23)/(2 xx 5 xx 10^4) cm` =`4 xx 10^-8 cm = 4 Å`. |
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