1.

If the velocity of hydrogen molecule is `5 xx 10^4 cm sec^-1`, then its de-Broglie wavelength is.A. `2 Å`B. `4 Å`C. `8 Å`D. `100 Å`

Answer» Correct Answer - B
(b) According to de-Broglie
`lamda = (h)/(mv) = (6.62 xx 10^-20 erg.sec)/((2)/(6.023 xx 10^23) xx 5 xx 10^4 cm//sec)`
=`(6.62 xx 10^-27 xx 6.023 xx 10^23)/(2 xx 5 xx 10^4) cm`
=`4 xx 10^-8 cm = 4 Å`.


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