1.

If the wavelength of photon emitted from an electron jump `n=4` to `n=2` in a `H-` like species is `1216 Å` then the species is `:`A. `H-` atomB. `He^(+)` ionC. `Li^(2+)`ionD. `Be^(3+)`ion

Answer» Correct Answer - 2
Energy of photon `=(124000)/(1216)=10.2eV=(H)_(2+1)=(He^(+))_(4rarr2)`
so, species is `He^(+)` ion


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