InterviewSolution
Saved Bookmarks
| 1. |
If the wavelength of the first line of the Balmer series of hydrogen atom is `656.1` `nm ` the wavelngth of the second line of this series would beA. `218.7 nm`B. `328.0 nm`C. `486.0 nm`D. 640.0 nm |
|
Answer» Correct Answer - C ( c) `(1)/(lamda_1) = R_H ((1)/(2^2) -(1)/(3^2)) = R_H ((5)/(36))` `R_H = (36)/(5 xx 656.1)` `(1)/(lamda_2)= R_H ((1)/(2^2) -(1)/(4^2))` `(1)/(lamda_2) = (36)/(5 xx 656.1) ((3)/(16))` `lamda = (5 xx 656.1 xx 16)/(3 xx 36) = 486.0 nm`. |
|