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| 1. |
If uncertainity in position of electron is `0.33 "pm"`. What will be uncertanity in its velocity ? |
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Answer» `Delta x = 0.33xx10^(-12)m^(-1)` `Delta v =(0.33xx10^(-12)) ge (h)/(4pi)= (6.626xx10^(-34))/(4xx3.14)` `implies Delta v ge 1.75xx10^(8)m//s` |
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