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If V1 is the voltage at port 1 and V2 is the voltage at port 2, then the attenuation in dB is?(a) 20 log10 (V1/V2)(b) 10 log10 (V1/V2)(c) 20 log10 (V2/V1)(d) 10 log10 (V2/V1)This question was posed to me in homework.Question is taken from Attenuators topic in section Filters and Attenuators of Network Theory

Answer»

The correct CHOICE is (a) 20 log10 (V1/V2)

For explanation I would SAY: If V1 is the voltage at PORT 1 and V2 is the voltage at port 2, then the ATTENUATION in dB is Attenuation in dB = 20 log10 (V1/V2) where V1 is the voltage at port 1 and V2 is the voltage at port 2.



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