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If vecA=3hati+4hatj and vecB=7hati+24hatj, find a vector having the same magnitude as vecB and parallel and same direction as vecA. |
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Answer» Solution :`|vecA|=sqrt(3^(2)+4^(2))=5` also `|vecB|=sqrt(7^(2)+24^(2))=25` desired VECTOR `=|vecB| hatA=25xx(3hati+4hatj)/(5)` `=5(3hati+4hatj)=15hatj+20hatj`. |
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