1.

If `x^(2)-y^(2) =1 , (x gt y)` ,then find the value of `log(x-y) (x+y)`A. -2B. 2C. -1D. 1

Answer» Correct Answer - C
Given `x^(2) - y^(2) =1`
Applying log on both the sides, we get
` Rightarrow [ ( x+y) (x-y) = -0`
` Rightarrow (x+y) + log ( x-y) =0`
` Rightarrow (x+y) = - log ( x-y)`
` ( log (x + y) )/)(log (x - y)0 = -1`
`Rightarrow log_(x-y) ( x+y) = -1`


Discussion

No Comment Found

Related InterviewSolutions