InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
If`x=asint-bcost ,y=acost+bsint ,"p r o v et h a t"``(d^2y)/(dx^2)=-(x^2+y^2)/(y^3)` |
|
Answer» Here, `x = asint - bcost` and `y = acost+bsint` `:. dy/dx = (dy/dt)/(dx/dt) = (-asint+bcost)/(acost+bsint)` Now, `(d^2y)/dx^2 = (d/dt(dy/dx))/(dx/dt) ` `=((-acost-bsint)(acost+bsint)-(-asint+bcost)(-asint+bcost))/((acost+bsint)^2(acost+bsint)` `=(-(acost+bsint)^2 - (bcost-asint)^2)/((acost+bsint)^3)` `=(-x^2-y^2)/(y^3)` `:. (d^2y)/dx^2 = (-(x^2+y^2))/(y^3).` |
|