Saved Bookmarks
| 1. |
If x - \(\frac{1}{x}\) = -1, find the value of x2 + \(\frac{1}{x^2}\) |
|
Answer» Here, we will use (a - b)2 = a2 + b2 - 2ab (x - \(\frac{1}{x}\)) = (-1) (x - \(\frac{1}{x}\))2 = (-1)2 (x)2 + (\(\frac{1}{x}\))2 - 2 x x x \(\frac{1}{x}\) = 1 x2 + \(\frac{1}{x^2}\) = 1 + 2 x2 + \(\frac{1}{x^2}\) = 3 |
|