If \(x + \frac{1}{x} = 3\), then find the value of \(x^2 + \frac{1}{x

1.	If \(x + \frac{1}{x} = 3\), then find the value of \(x^2 + \frac{1}{x^2}\).
Answer» \(x + \frac{1}{x} = 3\) Squaring both sides, \((x + \frac{1}{x})^2 = 3^2\) \(x^2 + \frac{1}{x^2} + 2 = 9\) \(x^2 + \frac{1}{x^2} = 9 -2 \) \(x^2 + \frac{1}{x^2} = 7\)

If \(x + \frac{1}{x} = 3\), then find the value of \(x^2 + \frac{1}{x^2}\).

Answer»

\(x + \frac{1}{x} = 3\)

Squaring both sides,

\((x + \frac{1}{x})^2 = 3^2\)

\(x^2 + \frac{1}{x^2} + 2 = 9\)

\(x^2 + \frac{1}{x^2} = 9 -2 \)

\(x^2 + \frac{1}{x^2} = 7\)

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