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If x = logb a, y = logc b, z = loga c, then xyz is(a) 0 (b) 1 (c) abc (d) a + b + c |
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Answer» (b) 1 Hint. x = logba ⇒ x = \(\frac{log_e\,a}{log_e\,b}\), y = logc b ⇒ y = \(\frac{log_e\,b}{log_e\,c}\), z = logac ⇒ z = \(\frac{log_e\,c}{log_e\,a}\). |
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