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If `|(x^(n),x^(n+2),x^(n+3)),(y^(n),y^(n+2),y^(n+3)),(z^(n),z^(n+2),z^(n+3))|` `= (x -y) (y -z) (z -x) ((1)/(x) + (1)/(y) + (1)/(z))`, then n equalsA. 1B. `-1`C. 2D. `-2` |
Answer» Correct Answer - B The degree of the determinant is `n + (n+2) + (n+3) = 3n +5` and the degree of the expression on RHS is 2. `:. 3n + 5 = 2 rArr n = -1` |
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