InterviewSolution
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InterviewSolution
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If x1, x2 are real roots of ax^2 – x + a = 0. Then, find the set of all values of parameter ‘a’ for which |x1 – x1| < 1?(a) (1 – 5a)/ a^2 < 0(b) (1 – 5a)/ a^2 = 0(c) (1 – 5a)/ a^2 > 0(d) (1 – 5a)/ a < 0I have been asked this question during an online interview.My question is from Applications of Quadratic Equations topic in portion Complex Numbers and Quadratic Equations of Mathematics – Class 11 |
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Answer» CORRECT CHOICE is (a) (1 – 5a)/ a^2 < 0 The EXPLANATION is: |X1 – x2| < 1 = (x1 – x2)^2 < 1 = (x1 + x2)^2 – 4 x1 x2 -1 < 0 = (1/a)^2 – 4 – 1 < 0 = (1 – 5a)/a^2 < 0. |
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